A 6.1kg bowling ball and a 7.2kg bowling ball rest on a rack 0.75 m apart. What is the force of gravity exerted on each of the balls by the other ball? G= Univ

Question

A 6.1kg bowling ball and a 7.2kg bowling ball rest on a rack 0.75 m apart.  What is the force of gravity exerted on each of the balls by the other ball? G= Universal Gravitational constant = 6.67 x 10^-11 N.m²/kg².

Answer 1

This is a "plug and chug" problem. The only snag would be to always make sure the units are S.I.

The force of gravity between two objects is jointly proportional to the object's masses and inversely proportional to the square of the distance:

F = G(M₁*M₂) / r²

F = 6.67E-11 (6.1*7.2) / (0.75)²

F = 5.21E-9 N (note this is in scientific notation) = 0.00000000521 N

Answer 2

Just use the formula for Universal Gravitation

                         F = G m₁m₂/R² = 6.67 x 10 ^-11 N m²/kg² x 6.1 kg x7.2 kg / (0.75)² m² = 4.8 x 10^-10N