08/09/13

Use the Laplace transform?
Use the Laplace transform to solve y^(4)-4y'''+6y"-4y'+y=0; y(0)=0, y'(0)=1, y"(0)=0, y'''(0)=1. Answer: y=te^t-t^2*e^t+(2/3)t^3*e^t L(y^(4))-4L(y''')+6L(y")-4L(y')+L(y)=L(0) But I don't know... more
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08/08/13

Use the Laplace transform?
Use the Laplace transform to solve y"-y'-6y=0; y(0)=1, y'(0)=-1. Answer: y=(1/5)(e^(3t)+4e^(-2t)) I don't know how to take the Laplace transform for both sides. Help me step by step.
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08/08/13

Find the inverse Laplace transform?
Find the inverse Laplace transform of F(s)=(8s^2-4s+12)/(s(s^2+4)). Answer: f(t)=3-2 sin 2t+5 cos... more
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08/05/13

Find the inverse Laplace transform?
Find the inverse Laplace transform of F(s)=(2s-3)/(s^2-4). Answer: f(t)=2 cosh 2t-(3/2) sinh 2t
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08/05/13

What comes after partial differential equations?
What math comes after partial differential equations for physics and electrical engineering majors?
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08/05/13

How to find the inverse laplace transform on Ti-89 calculator?
Can you give me step by step procedure?
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08/05/13

Find the inverse Laplace transform?
Find the inverse Laplace transform of F(s)=(2s+2)/(s^2+2s+5). Answer: f(t)=2e^-t*cos 2t
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08/04/13

Find the inverse Laplace transform?
Find the inverse Laplace transform of F(s)=3s/(s^2-s-6). Answer: f(t)=(9/5)e^3t+(6/5)e^-2t  
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08/04/13

Find the inverse Laplace transform?
Find the inverse Laplace transform of F(s)=2/(s^2+3s-4). Answer: f(t)=(2/5)e^t-(2/5)e^-4t Never mind, I now know how to do it. But can someone tell me how to find the answer on Ti-89 calculator?
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08/03/13

Find the Laplace transform?
Find the Laplace transform of f(t)=te^at. Answer: F(s)=1/(s-a)^2, s>a
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08/03/13

Find the Laplace transform?
Find the Laplace transform of f(t)=cos at, where a is a real constant. Answer: F(s)=s/(s^2+a^2), s>0  
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08/03/13

Find this improper integral?
Find the improper integral of te^-st dt from 0 to b where the limit of b approaches to positive infinity.
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08/03/13

Help me with this problem?
Show that (ln x)y"+(1/2)y'+y=0 has a regular singular point at x=1.
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07/31/13

Find the indicial equation?
Find the indicial equation, the recurrence relation, and the roots of the indicial equation for 2xy"+y'+xy=0. Answer: r(2r-1)=0; an= -(an-2/((n+r)[2(n+r)-1]; r1=1/2, r2=0 I used the substitution... more
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07/31/13

Find all values?
Find all values of α for which all solutions of x^2*y"+αxy'+(5/2)y=0 approach zero as x→0. Answer: α<1
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07/31/13

Find all singular points?
Find all singular points of xy"+(1-x)y'+xy=0 and determine whether each one is regular or irregular. Answer: x=0, regular I know that x=0 but I need to take the limit as x approaches to 0 but... more
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07/30/13

Find the solution?
Find the solution of 4x^2*y"+8xy'+17y=0, y(1)=2, y'(1)=-3. Answer: y=2x^(-1/2)*cos(2*lnx)-x^(-1/2)*sin(2*lnx) y=x^r y'=rx^r-1 y"=r(r-1)x^r-2 r=-1/2±2i What's the general solution for this?
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07/29/13

Find the general solution?
Find the general solution of x^2*y"+3xy'+5y=0 that is valid in any interval not including the singular point. Answer: y=c1*x^-1*cos(2*ln abs(x))+c2*x^-1*sin(2*ln... more
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07/29/13

Find the general solution?
Find the general solution of (x+1)^2*y"+3(x+1)y'+0.75y=0 that is valid in any interval not including the singular point. Answer: y=c1*abs(x+1)^(-1/2)+c2*abs(x+1)^(-3/2)
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07/28/13

How to simplify this?
x^2(a(a-1)x^(a-2))+4x(ax^(a-1)) How does the expression above simplify to a(a-1)x^a+4ax^a?
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07/28/13

Find the general solution?
Find the general solution of x^2*y"+4xy'+2y=0 that is valid in any interval not including the singular point. Answer:... more
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07/28/13

Rewrite this as a sum?
Rewrite sigma from n=2 to infinity of n(n-1)anxn-2 as a sum whose generic term involves xn. Answer: sigma from n=0 to infinity of (n+2)(n+1)an+2xn Please help me step by step.
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07/28/13

Compute y' and y"?
Given that y=sigma of n=0, infinity of nx^n, compute y' and y" and write out the first four terms of each series as well as the coefficient of x^n in the general term. Answer:... more
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07/26/13

Find a formula involving integrals?
Find a formula involving integrals for a particular solution of y'''-y"+y'-y=g(t). Answer: Y(t)=(1/2)∫(from to to t) [e^(t-s)-sin(t-s)-cos(t-s)]g(s)ds
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07/26/13

Find the general solution?
Find the general solution of y(4)-y=3t+cos t. Answer: y=c1et+c2e-t+c3cos t+c4sin t-3t-(1/4)t*sin t r=1, -1, i, -i, But how do I figure out the form of the particular solution?
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