
Maurizio T. answered 07/28/13
Statistics Ph.D and CFA charterholder with a true passion to teach.
Hi Sun, about this problem, assume that m ranges from 0 to ∞.
Let n=m+2. This is correct since when m=0 we have n=2, when m=1, we have n=3, and so on.
Then, you can write your summation as
Σn=2∞ (n)(n-1)an xn = Σm=0∞ (m+2)(m+2-1)am+2xm+2-2 = Σm=0∞ (m+2)(m+1)am+2xm
which is exactly your answer. I wrote m, instead of n, but this does not change anything as n or m are just names. It is actually more precise to change the name of the index from n to m as in this way you show to someone following your argument what you did. Hope this helps.
Best Regards,
Maurizio