8 Answered Questions for the topic Improper Integrals

Improper Integrals Calculus Integrals Integration

11/20/21

How do you tell when an improper integral converges or diverges? (specific question)
Hello! I'm having trouble understanding why the improper integral I'm answering is labeled as divergent when it looks like it converges. The improper integral is 1/x3, in-between the interval [-1,... more
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Improper Integrals

07/27/18

Convergence of Integral of 1/sqrt(x+x^3) using Limit Comparison Test
I tried to get the answer by using the LCT, and it led me to the cpnclusion that the integral diverges since the integral from 0 to 1 diverges, then the whole integral also does it
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Improper Integrals

07/09/15

Compute the value of the following improper integral
Compute the value of the following improper integral ∫(5(ln(x)))/x^(8)dx, from 1 to infinity =Does the series ∑ (5(ln(n)))/(n^(8))dx, from n=1 to infinity converge or diverge? Hint:Use integration... more
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Improper Integrals Calculus 2

10/06/14

One last Calc 2 Question: Improper Integrals
I got all the way through this problem and the answer seemed legitimate, but I did not get the correct answer. Thank you in advance for any help. I really appreciate it.   Find the volume of the... more
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Improper Integrals

08/03/13

Find this improper integral?
Find the improper integral of te^-st dt from 0 to b where the limit of b approaches to positive infinity.
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Improper Integrals

05/04/13

give me a formal proof of comparison test for improper integrals
please i need a formal proof of comparison test for improper integrals..
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Improper Integrals Math

02/02/13

How do i integrate 4x^2/(x^3-8) from 0 to 8
How do I integrate 4x^2/(x^3-8) from 0 to 8 It is an improper integral and I know it diverges but I don't know why  i found u=x^3-8 but am getting stuck after that  
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Improper Integrals Algebra

11/19/12

Improper integrals and comparison tests
I have this problem:  Evaluate the integral (x^2-2)/(x^4+3) from 1 to infinity using a comparison test (evaluate if converging).  I understand the basic idea is to find a function with a graph... more
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