I'm having trouble solving this problem.
I'm having trouble solving this problem.
The original equation is: cos(x^2y^2)/sin(x^2y^2)=2x I simplified it to cot(x^2y^2)=2 I used chain rule to get -csc^2u * du/dx and found du/dx= (2x^2yy'+2y^2x) new...
Suppose y is defind implicitly as a function of x by the following equations, where g is a given differentiable function of one variable. Find an expression for y'. a. xy=g(x)+y3 Ans:...
(x2/a2) + (y2/b2)=1 Point (m,n) Answer should be in terms of x,y,m,n,a,b and answer is _______=1
At what point is the tangent line to the curve y^3=2x^2 perpendicular to the line x-2y-10=0 ? (x,y) format
Find d^2y/dx^2 x^6y^2-4=0
Differentiate by using chain rule y=(2×^3-7)^4
I think you're supposed to use implicit differentiation, and then solve for the equation after finding the slope.
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the position function s of a point is given by two dimensional quantities where t in seconds and the y direction is affected by gravity (10m/s/s). y(t)=4t*sin(θ) - 5t2 ...
It's Calculus. Implicit differentiation is used.
Find the points where the following graph has a vertical tangent line. 4x2 + y2 -8x + 4y + 4=0