Marc L. answered 11/27/20
Helping others understand things one step at a time
I'm going to define y' as dy/dx, now lets start by taking the first derivative:
8y'/(8y)=5y+5xy', y'-5xyy'=5y2, y'(1-5xy)=5y2, y'=5y2/(1-5xy)
now lets let y'' be d2y/(dx2) and take the second derivative:
y''=((1-5xy)(10yy')-(5y2)(5y+5xy'))/(1-5xy)2
Now wherever you see a y', replace it with the equation we had above y'=5y2/(1-5xy):
y''=((1-5xy)(10y(5y2/(1-5xy)))-(5y2)(5y+5x(5y2/(1-5xy))))/(1-5xy)2 (I will leave the simplifying to you)
there is your second derivative
now for part b) set y''=0 and solve for the values of x and y that satisfy that equation