Differentiating we have

2xy + x^{2}y' + y^{2} + 2xyy' = 0 Collecting terms, we have

**y' = -(y**^{2}** + 2xy)/(x**^{2 }**+ 2xy)**

(I assume it is ok to leave y' in terms of both x & y)

Mr C.

asked • 10/04/19
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Differentiating we have

2xy + x^{2}y' + y^{2} + 2xyy' = 0 Collecting terms, we have

**y' = -(y**^{2}** + 2xy)/(x**^{2 }**+ 2xy)**

(I assume it is ok to leave y' in terms of both x & y)

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