
Dayv O. answered 09/25/24
Caring Super Enthusiastic Knowledgeable Calculus Tutor
sec(pi*x/4)tan(pi*x/4) = [sqrt(2)-4]x + 4
sec(π/4)tan(π/4)=[(√2)-4]x+4
sec(π/4)=√2
tan(π/4)=1
have x=[(√2)-4]/[(√2)-4}=1
Solved this using a calculator, but wanted to know if it can be done, at least partially, by hand. Not looking for all solutions of x (unless there's a general formula). Just the lowest, positive x value this equation is true
sec(pi*x/4)tan(pi*x/4) = [sqrt(2)-4]x + 4
Dayv O. answered 09/25/24
Caring Super Enthusiastic Knowledgeable Calculus Tutor
sec(pi*x/4)tan(pi*x/4) = [sqrt(2)-4]x + 4
sec(π/4)tan(π/4)=[(√2)-4]x+4
sec(π/4)=√2
tan(π/4)=1
have x=[(√2)-4]/[(√2)-4}=1
The secant is the reciprocal of the cosine function (1/cos). The tangent is equal to the sine function divided by the cosine function.
So sec × tan = sin / cos2 = sin ( x ) / [ 1 - sin( x2 ) ].
I would start here. When I have more time, I will get back to this. The bat phone just rang!
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.