So your estimate for p is 49/219 ≈ 0.2237. We'll use this in the Margin of Error formula for sample proportions
M.E. = Zα/2•√(p•(1-p)/n)
= 3.291•√(0.2237•0.7743/219)
= 0.092554
Rounding to 3 decimal places, the margin of error is about 9.3%.
Paula L.
asked 02/19/24Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 214 with 49 successes at a confidence level of 99.9%.
M.E. = %
(report answer accurate to one decimal place; answer should be reported as a percent, not a decimal—though do not type the percent sign)
Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
So your estimate for p is 49/219 ≈ 0.2237. We'll use this in the Margin of Error formula for sample proportions
M.E. = Zα/2•√(p•(1-p)/n)
= 3.291•√(0.2237•0.7743/219)
= 0.092554
Rounding to 3 decimal places, the margin of error is about 9.3%.
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