Let H be the distance from the floor to the top of the ladder and L = distance from the wall to the bottom of the ladder.
Let H2+L2=100, then H=√100-25=5√3. Take the derivative to find 2HdH/dt+ 2LdLdt=0. Thus dL/dt=-H/LdH/dt. Note dL/dt is the speed of the bottom and dH/dt is the speed of the top. So, dL/dt=-5√3/5*2=2√3 ft/sec