
Rachel M. answered 11/01/23
Applied Mathematician who just Loves Math
Hello Ansaf, let's see if we can solve this.
As I read it, this is a Simple Interest problem. This means that we will use the formula for Simple Interest which is as follows:
I=P*r*t
I = Interest ($)
P = Initial Value, or the Principal value. ($)
r = The rate at which you're building interest. This value is the decimal form of the percentage.
t = The time you spend building interest in years.
In this problem, you can get the solution by treating your problem as a summation of two different Simple Interest formulas.
IT=P1*r1*t+P2*r2*t
Note: Since both interests are occurring over the same time interval, we only need 1 time variable.
Now let's look at the problem.
We can see one set of interest has a rate of 9.4%, or 0.094. The other has a rate of 7.2%, or 0.072. Let's use these values as our r1 and r2 respectively. We can see this happens over the course of only 1 year so t can be 1. We also know that the total interest at the end of the year is $863.30 so let's make this our total interest value, IT.
To recap:
r1=0.094
r2=0.072
t=1
IT=863.30
This takes care of everything but two variables. The general rule is 1 equation per 1 unknown. This means we need a formula to relate the two initial amounts. Since we know the bank loaned a total amount of $9900, we can say that both initial amounts will sum to this number. Thus: P1+P2=9900 Since we are solving for the initial amount that gets lent at the rate of 9.4%(P1), let's rewrite this formula as this so we don't have to solve for it later:
P2=9900-P1
Now that we have collected our variables, we can plug into the original formula we made.
IT=P1*r1*t+P2*r2*t
863.30=P1*0.094*1+(9900-P1)*0.072*1
Solving this we get:
863.30=P1*0.094+(9900-P1)*0.072
863.30=0.094P1+712.8-0.072P1
863.30=0.022P1+712.8
150.51=0.022P1
Being mindful to get our units, we get the answer:
P1=$75250/11, or approximately $6840.91