Take d/dx of every term of the equation: 2sec(x)(sec(x)tan(x)) + 2csc(y)(-csc(y)cot(y))dy/dx = 0
y' = sec2xtanx/csc2ycoty (check)
Kevin J.
asked • 10/23/23Use implicit differentiation
9. y' of sec²(x) + csc²(y) = 9
ans. y'= tan(x) sec²(x) / cot(y) csc²(y)
Follow
•
1
Add comment
More
Report
1 Expert Answer
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
