Inactive Tutor answered 10/23/23
Tutor
New to Wyzant
y'- (-1/(1+(xy)2)(xy'+y)= 0
y'+xy'/(1+x2y2)+y/(1+x2y2) = 0
y'(1+x/(1+x2y2)) = -y/(1+x2y2)
y'(1+x2y2+x) = -y
y' = -y/(1+x2y2+x) = -y(x2y2+1+x)
Kevin J.
asked 10/23/2310. y - Arccot(xy) = 3
Inactive Tutor answered 10/23/23
y'- (-1/(1+(xy)2)(xy'+y)= 0
y'+xy'/(1+x2y2)+y/(1+x2y2) = 0
y'(1+x/(1+x2y2)) = -y/(1+x2y2)
y'(1+x2y2+x) = -y
y' = -y/(1+x2y2+x) = -y(x2y2+1+x)
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