
Bradford T. answered 10/23/23
Tutor
4.9
(29)
Retired Engineer / Upper level math instructor
y'- (-1/(1+(xy)2)(xy'+y)= 0
y'+xy'/(1+x2y2)+y/(1+x2y2) = 0
y'(1+x/(1+x2y2)) = -y/(1+x2y2)
y'(1+x2y2+x) = -y
y' = -y/(1+x2y2+x) = -y(x2y2+1+x)