
Kevin P. answered 10/23/23
Graduate Student in Statistics with 10 years of Tutoring experience
Hello Kevin,
For your question:
a. y = Arcsec(sec(2x))
The derivative of arcsec() is uncommon to be seen. But for simplicity's sake,
d/dx(arcsec(x)) = 1/(abs(x)*sqrt(x^2-1))
So, with that in mind:
d/dx(y) = d/dx(arcsec(sec(2x)))
= 1/(abs(sec(2x))*sqrt((sec(2x))^2 -1))*d/dx(sec(2x))*d/dx(2x) through chain rule.
The rest I will leave for you to simplify.
b. y = Arcsin(cos(t))
d/dt(y) = 1/sqrt(1-(cos(t))^2)*d/dt(cos(t)) through chain rule.
I will leave the rest for you to simplify
c. h = sin(arccos(z))
d/dz(h) = d/dz(sin(arccos(z)))
= cos(arccos(z))*d/dz(arccos(z)), recall that d/dz(arccos(z)) = -1/sqrt(1-x^2)
The rest I will leave for you to simplify.
Hope this helps!