
Bradford T. answered 10/24/23
Retired Engineer / Upper level math instructor
An alternate way, same answer
x = ln(x+y+1)
Take e to the power of both sides
ex= eln(x+y+1) = x+y+1
Doing implicit derivation
ex=1+y'
y'=ex-1
y'=eln(x+y+1)-1
y'=x+y+1-1 = x+y