Inactive Tutor answered 10/24/23
An alternate way, same answer
x = ln(x+y+1)
Take e to the power of both sides
ex= eln(x+y+1) = x+y+1
Doing implicit derivation
ex=1+y'
y'=ex-1
y'=eln(x+y+1)-1
y'=x+y+1-1 = x+y
Kevin J.
asked 10/20/23Use implicit and/or logarithmic differentiation to find the derivative y' of: Write the solution of each number
9. x = ln(x+y+1)
ans. y' = x + y
Inactive Tutor answered 10/24/23
An alternate way, same answer
x = ln(x+y+1)
Take e to the power of both sides
ex= eln(x+y+1) = x+y+1
Doing implicit derivation
ex=1+y'
y'=ex-1
y'=eln(x+y+1)-1
y'=x+y+1-1 = x+y
Inactive Tutor answered 10/20/23
x = ln(x + y + 1); 1 = (1 + y')/(x + y + 1); x + y + 1 = 1 + y'; y' = x + y
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