dV/dt=4pir^2dr/dt ... dr/dt=dV/dt/(4pir^2)=2.2/(4pi(1.1)^2= .144 ... dDiameter/dt = .288 ft/min
Landon B.
asked • 10/02/23Calculus Question
A spherical balloon is inflated so that its volume is increasing at the rate of 2.2 cubic feet per minute.
How rapidly is the diameter of the balloon increasing when the diameter is 1.1 feet?
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