Mark M. answered 09/27/23
Retired math prof. Very extensive Precalculus tutoring experience.
f'(x) = limh→0 [f(x+h) - f(x)] / h
So, if f(x) = x2, then the value of the given limit is f'(x), which is 2x.
Kevin J.
asked 09/27/231. lim (x+h)²-x²/ h
h-->0
Mark M. answered 09/27/23
Retired math prof. Very extensive Precalculus tutoring experience.
f'(x) = limh→0 [f(x+h) - f(x)] / h
So, if f(x) = x2, then the value of the given limit is f'(x), which is 2x.
Yefim S. answered 09/27/23
Math Tutor with Experience
1. lim (x+h)²-x²/ h = lim (2xh + h2/ h = lim(2x + h) = 2x = f'(x).
h-->0 h-->0 h-->0
Answer: 2x
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