AJ L. answered 05/09/23
Tutor
4.7
(79)
SAT Math Specialist
Recall the binomial probability formula P(X=x) = C(n,x)pxqn-x where q=1-p and C(n,x) = n!/[x!(n-x)!]
P(X=1) = C(7,1)(0.02)1(0.98)6 ≈ 0.124
Therefore, the probability of selecting one with a defect is about 0.124
Hope this helped!
AJ L.
Please feel free to schedule a lesson with me if you need more assistance with Probability!05/09/23