
Juan M. answered 04/30/23
Professional Math and Physics Tutor
To determine whether the vector field F is conservative, we need to check if it satisfies the condition that the curl of F is zero. That is,
curl(F) = ∂Q/∂x - ∂P/∂y = 0
where F = (P, Q).
Here, we have P = 7x + 4y and Q = 4x + 5. Therefore,
∂Q/∂x = 4 and ∂P/∂y = 4
Since these partial derivatives are equal, the curl of F is zero, and the vector field F is conservative.
To find a potential function f, we need to find a function whose gradient is equal to F. That is,
∇f = (7x+4y, 4x+5)
Integrating the first component with respect to x gives:
f(x,y) = 7/2 x^2 + 4xy + g(y)
where g(y) is a constant of integration with respect to x.
Taking the partial derivative of f with respect to y gives:
∂f/∂y = 4x + g'(y)
Comparing this with the second component of F, we have:
g'(y) = 5
Integrating with respect to y gives:
g(y) = 5y + K
where K is a constant of integration. Therefore, the potential function f is:
f(x,y) = 7/2 x^2 + 4xy + 5y + K
where K is an arbitrary constant. Thus, we have found a potential function f for the vector field F, and it is given by the equation above.