Kitty F. answered 07/13/23
MSE degree in electrical engineering with 10+ teaching experience
No picture available.
Ritz S.
asked 04/04/23Link attached for pic: https://ibb.co/BjR9grL
Solve for: (2 decimals)
a. Equivalent wye-connected load:
ZA = Blank 1 Blank 2 jBlank 3 ohms
ZB = Blank 4 Blank 5 jBlank 6 ohms
ZC = Blank 7 Blank 8 jBlank 9 ohms
b. Line currents:
IaA = Blank 10 ∠ Blank 11° A
IbB = Blank 12 ∠ Blank 13° A
IcC = Blank 14 ∠ Blank 15° A
c. voltage drop in the lines:
For phase A = Blank 16 ∠ Blank 17° V
For phase B = Blank 18 ∠ Blank 19° V
For phase C = Blank 20 ∠ Blank 21° V
Kitty F. answered 07/13/23
MSE degree in electrical engineering with 10+ teaching experience
No picture available.
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