Matthew N. answered 03/25/15
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Hi Katie,
Remember, probability always boils down to:
desired outcome
total possible outcomes
So, we want our second apple to be red.
There are 2 ways this can happen independently:
Either our first apple AND our second apple are both red . . .
OR the first apple is yellow, and the second is red.
First, the chances that both are red:
6 * 5 = 30 = 1
10 9 90 3
(You multiply because the probability of the second selection depends on the first.)
Next, the chances that only the second is red:
4 * 6 = 24 = 4
10 9 90 15
To find the chance that one OR the other happens, you ADD:
1 + 4 = 5 + 4 = 9 = 3
3 15 15 15 15 5
To answer your second question, remember this handy rule:
To find the probability that "at least one" thing happens,
find the probability of "none" happening, and subtract that from 1.
So, what are the chances that in 2 selections, none are red?
4 * 3 = 12 = 2
10 9 90 15
1 - 2/15 = 15/15 - 2/15 = 13/15