Jerry F. answered 02/03/23
Compassionate teacher of math & physics (for a few decades)
Let B = # of boys; G = # of girls.
G/B = 3/4 is the FIRST given condition. Cross multiply to get 3B = 4G, then divide both sides by 3 to arrive at
B = 4G/3.
The SECOND given condition is B - G = 34. Replace B with 4G/3 to get 4/3G-G = 34 or 4/3G-3/3G = 34.
Finally, 1/3G = 34. Multiply both sides by 3 to yield 3/3G = 3(34), or G = 102.
Jerry F.
This is an example of two equations involving the same two unknowns, or simultaneous equations. So long as there are as many true INDEPENDENT equations as there are unknown quantities, the unknowns can be determined. It would be wise to look up the meaning of independent equations.02/03/23