mom asked a vendor to give 20 kilograms of rice worth Php 1,920. The available variety of rice is JWR at Php 90 per kg and BR at Php 100 per kg. How many kilos of each variety should the vendor mix?

Question

Can someone help me get the answer to this along with the

Representation

Equation

and Solution?

Answer 1

Let X be the varity of rice JWR , and Y be the varity of rice BR .

aso given that price of JWR type rice Php 90 per k.g and BR type rice Php 100

then acoording to question :-

X+ Y = 20 ..................... (1)

90*X + 100*Y + 1920 ....................(2)

now multiplying by 90 in equation (1) we get ......

90*X + 90*Y =1800 .................(3)

now sustracting equetion (3) by equation (2) we get .........

10Y = 120

Y =12

now putting value of Y in equation (1) we get........

X = 8

so number of k.g of JWR type rice X = 8 k.g

and number of k.g of BR type rice Y = 12 k.g

Answer 2

J is kg of JWR (90 Php/kg)

B is kg of BR (100 Php/kg)

J + B = 20 (total wt.) so B = 20 - J

For value: 90J + 100B = 1920

Substituting: 90J + 100(20 - J) = 1920

90J + 2000 - 100J = 1920

-10J = - 80; J = 8 kg; B = 12 kg.

Check: 90(8) + 100(12) = 720 + 1200 = 1920 Php