line equation’s

Question

what is an equation of the line that passes through the points (6,-2) and (-4,-2)

Answer 1

find the slope first: m=y2−y1x2−x1m equals the fraction with numerator y sub 2 minus y sub 1 and denominator x sub 2 minus x sub 1 end-fraction

𝑚=𝑦2−𝑦1𝑥2−𝑥1

y−y1=m(x−x1)y minus y sub 1 equals m open paren x minus x sub 1 close paren

𝑦−𝑦1=𝑚(𝑥−𝑥1)

with the point (6,-2)open paren 6 comma negative 2 close paren

(6,−2)

and m=0m equals 0

𝑚=0

, we find the equation:

y−(-2)=0(x−6)y minus open parentheses negative 2 close parentheses equals 0 open parenthesesx minus 6 close parentheses

𝑦−(−2)=0(𝑥−6)

y+2=0y plus 2 equals 0

𝑦+2=0

minus 2 to both sides

y= -2

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