Convert C in to assembly language.

Question

Convery the following C code in to MIPS assembly code

 

int a;       // global variable

int main(void)

{

int Q[15];  // array of integers stored at the base address of 0x43210000

int ECE375[15];  // array of integers stored at the base address of 0xBBBB0000

for(int i = 0; i $\leq$ 15; i= i+1)

        ECE375[i] = Q[i] + 2;

int t;

int c = 3; 

a = dofsum(7, 5, c);

t = a - 4;

return t;

}

 

int dofsum(int q1, int q2, int q3)

{

int total, psum1, psum2;

psum1 = sum(q1 + q2);

psum2 = sum(q3 + 4);

total = psum1 - psum2;

return total;

}

 

int sum(int x, int y)

{

int total;

total = x + y;

return total;

}

Answer 1

.data

a: .word 0

Q: .space 60

ECE375: .space 60

.text

.globl main

main:

# Initialize i to 0

li $t0, 0

# Loop from 0 to 14 inclusive

for_loop:

slti $t1, $t0, 15

beq $t1, $zero, end_for

# Load value from Q[i] into $t2

la $t3, Q

addu $t3, $t3, $t0

lw $t2, ($t3)

# Add 2 to $t2 and store the result in ECE375[i]

addi $t2, $t2, 2

la $t3, ECE375

addu $t3, $t3, $t0

sw $t2, ($t3)

# Increment i by 1

addi $t0, $t0, 1

j for_loop

end_for:

# Call dofsum(7, 5, 3) and store the result in a

li $a0, 7

li $a1, 5

li $a2, 3

jal dofsum

sw $v0, a

# Subtract 4 from a and store the result in t

lw $t0, a

li $t1, 4

sub $t0, $t0, $t1

sw $t0, ($sp)

# Return t

jr $ra

# dofsum(q1, q2, q3)

# Returns the difference between the sums of q1+q2 and q3+4

dofsum:

# Save the return address and the current frame pointer

addi $sp, $sp, -8

sw $ra, 4($sp)

sw $fp, 0($sp)

addi $fp, $sp, 8

# Call sum(q1, q2) and store the result in psum1

add $a0, $a0, $a1

jal sum

move $s0, $v0

# Call sum(q3, 4) and store the result in psum2

li $a0, 4

add $a0, $a0, $a2

jal sum

move $s1, $v0

# Subtract psum2 from psum1 and return the result

sub $v0, $s0, $s1

# Restore the previous frame pointer and the return address

lw $ra, 4($fp)

lw $fp, ($fp)

addi $sp, $sp, 8

jr $ra

# sum(x, y)

# Returns the sum of x and y

sum:

add $v0, $a0, $a1

jr $ra