Peter R. answered 11/09/22
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Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
6L/2H = 3 times as many low calorie than high calorie. (3L for every 1H).
Renita D.
asked 11/09/22A restaurant had six items on the menu that were low calories and two that were high calorie. How many times more low calorie items are there than high calorie?
Peter R. answered 11/09/22
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
6L/2H = 3 times as many low calorie than high calorie. (3L for every 1H).
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Renita D.
Thank you so much!11/10/22