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Express in simplest form

3n/n^2-49 - 2/3n+21

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Robert J. | Certified High School AP Calculus and Physics TeacherCertified High School AP Calculus and Ph...
4.6 4.6 (13 lesson ratings) (13)
1

3n/(n^2-49) - 2/(3n+21) <==Is this what you want?

LCD = 3(n+7)(n-7)

3n/(n^2-49) - 2/(3n+21)

= (9n - 2(n-7))/LCD

= (7n + 14)/LCD

= 7(n+2)/[3(n+7)(n-7)] <==Answer

Patricia M. | Strong in both Math and English plus Test Prep (ACT,SAT,ASVAB,GED...)Strong in both Math and English plus Tes...
4.9 4.9 (174 lesson ratings) (174)
0

Let me be sure about the format of this expression before I give you a solution, because it will definitely make a difference! May I take this expression literally, as it is written? Or is it actually a difference of two fractions... in other words,  with 3n being the numerator of the first fraction, n-squared minus 49 the denominator of the first fraction; 2 being the numerator of the second fraction, and 3n+21 the denominator of the second fraction?  That would make it: 3n/(n^2-49) - 2/(3n+21).

If you are studying order of operations, your original format makes sense. If you are studying factoring, the  alternate format I described would make more sense. 

Note: I didn't notice earlier that Robert J. has answered, making the same assumption that I have... your solution is there.