
Ryan C. answered 07/05/22
Ivy League Professor | 10+ Years Experience | Patient & Kind
Hi Adrian,
Thanks for your question!
Newton's law of cooling states
dT/dt = -k*(T-T0),
where T(t) is the temperature (measured in degF) of the lasagna at time t (measured in minutes), k is a positive constant related to the thermal conductivity of the lasagna (how fast/slow the lasagna cools), and T0 is the temperature of the kitchen (which is 72 F according to this problem).
This differential equation is separable, meaning we can write the equation as follows:
dT/(T-T0) = -k*dt.
The LHS just depends on T (since T0 is constant) and the RHS just depends on t (since k is constant). We can integrate both sides of this equation to get
∫dT/(T-T0) = ∫-k*dt + C,
ln(T-T0) = -kt + C,
where C is an arbitrary constant of integration. Solving for T, we get
T(t) = T0 + e-kt + C.
Since C is an arbitrary constant, we can redefine a new arbitrary constant D = eC, so that our solution above becomes
T(t) = T0 + De-kt.
We know that T0 = 72 F. It remains to be seen what D and k equal.
Since the lasagna is taken out of an oven with temperature 375 F, we can assume the lasagna has an initial temperature of 375 F. In other words, T(0) = 375 F. Plugging t = 0 into our formula for T(t) above, we find
T(0) = T0 + De-k(0)
375 = 72 + D,
so that D = 303 F. Now, our formula for T(t) is
T(t) = 72 + 303e-kt.
We still don't know the value of k in this formula. To compute this value, we use the fact that the temperature of the lasagna after 7 minutes is 309.2 F. In other words, T(7) = 309.2 F. Plugging t = 7 into our formula for T above, we get
T(7) = 72 + 303e-k(7),
309.2 = 72 + 303e-7k.
Solving for k, we find
k = -ln(237.2/303)/7 ∼ 0.0349755912 min-1.
Our updated formula for T(t) is now
T(t) = 72 + 303e-(0.0349755912)t.
To finish this question, we must determine the temperature of the lasagna at t = 17 min, so we compute
T(17) = 72 + 303 303e-(0.0349755912)(17) ∼ 239 F.
Thus, the final answer is A. The lasagna is roughly 239 F after 17 min.