Raymond B. answered 05/24/22
Math, microeconomics or criminal justice
460 = 304e^rt where r = 0.011 and t = years after 2008
460/304 = e(.011)t
ln(460/304) = 0.011t
t = ln(460/304)/.011 = 37.65
t = 37.65 years to reach 460 million
2008 + 38
= 2046 AD or CE = the year when population reaches 406 million
but your problem uses a slightly different model as if population doesn't grow continuously but only annually, which is "close" but clearly not how population grows, realistically.
so
460 = 304(1+ .011)^t
460/304 = 1.011^t
solve for t
1.5132 = (1.011)^t
t = the power, the exponent that makes 1.011 = 1.5132
t > 32 years using a simple calculator, but probably not much more
t = a little less than 37 years
year about 2008+37 = 2045 AD
with just annual compounding, it grows slightly less slowly than with continuous compounding