A function is given.

Question

h(t) = 2t2 − t; t = 3, t = 8

(a) Determine the net change between the given values of the variable.

(b) Determine the average rate of change between the given values of the variable.

Answer 1

Assuming you meant h(t) = 2t² - t then for question (a) the net change is h(8) - h(3)

h(8) = 2(8)² - (8) = 120

h(3) = 2(3)² - (3) = 15

So the net change in value is 120 - 15 = 105

The average rate of change is the slope between the two points (3, 15) and (8, 120) = (120 - 15)/(8 - 3) = 105/5 = 21