Raymond B. answered 05/22/22
Math, microeconomics or criminal justice
f(x) = 3x^2 +5
f(x+2) = 3(x+2)^2 + 5 = 3(x^2 + 4x +4) + 5 = 3x^2 + 12x + 12 + 5
= 3x^2 + 12x + 17
While if x=2, then
f(x) + f(2) = f(2) + f(2) = 2f(2)
= 2(3(2)^2 12(2)+ 5)
= 2(12+ 5) = 2(17) = 34
BUT if the x in f(x) isn't the same as the x=2 in f(2) which seems likely
f(x+2) = f(x) + f(2) when
3x^2 + 12x + 17 = 3x^2 + 22
12x = 22-17 = 5
x = 5/12
f(x+2) = f(x) + f(2) when x = 5/12
3(5/12)^2 + 12(5/12) +17
= 75/144 + 5 + 17
= 3243/144 = about 22.5
3(5/12)^2 +22
= 75/144 + 3168/144
= 3243/144 = about 22.5
then f(x) + f(2)
= 3x^2 + 5 + f(2)
= 3x^2 +5 + 3(2)^2 + 5
= 3x^2 + 5 + 17
= 3x^2 + 22
f(x) + f(2) then differs from f(x+2) by 12x -5, close but still different if x=2
buy f(x+2) = f(x) +f(2) if x= 5/12