Help me please with math

Question

the braking distance of a car varies directly as the square of the speed of that car. Assume that a car traveling 35 miles per hour can stop 43 feet after the brakes are applied. how long is the braking distance for the same care traveling at 65

Answer 1

D = kS^2

43 = k(35^2) = 1225k

k = 43/1225

D = (43/1225)S^2

D = (43/1225)(65^2)

= 43(4225)/1225

= about 148.31 feet

= stopping distance going 65 mph