The other situation in which rational fractions misbehave is at a zero of the denominator.
When the numerator is non-zero and the denominator is 0, the fraction is undefined and has a non-removable discontinuity.
The tricky situation is when both numerator and denominator are zero at the limit. Here, l'Hospital's rule will work but it is usually easier to find the factor common to the numerator and denominator and divide it out.
Example:
lim x->1 of (x2 + x -2)/((x2 - 1) = lim x->1 (x+2)/(x+1) = 3/2.