X^2(x+3)(x-b)=0

Question

In the given equation, b is a positive constant. The sum of the solutions of the equation is 5. What is the value of b?

Answer 1

X^2(x+3)(x-b)=0

x² = 0

x =√0

x= 0 Note: English/German mathematicians regard zero as neither positive or negative and having its own category; not a positive constant

(x+3) = 0 then x = -3

(x-b) = 0 then x = b; this solution will give 0 for any value of b since x = b

and b is a positive constant

since x = b is a solution, according to the information given x = 0 is not a solution because 0 is not a positive constant.

Sum

- 3 + b = 5

b = 5 + 3

b = 8

x = b = 8

8²(8+3)(8-8)=0

16(11)(0) =0

0 = 0

I hope this helps.

Answer 2

x + (-3) + b = 5