Solve the equations from parts a and b.

Question

Find the dimensions of a rectangle given that its perimeter is 80 cm and its length is 1 cm more than twice its width.

 

Set up your solution using the variables L for the length, W for the width, and P  for the perimeter. 

 

Part a: Using the definition of perimeter, write an equation for P  in terms of L and W .

 

Part b: Using the relationship given in the problem statement, write an equation for L in terms of W .

Answer 1

2L + 2W = 80

L = 1+ 2W

L+W = 40

L =40-W = 1+2W

3W = 39

W = 13 cm Wide

L = 27 cm Long