f(x)=x32 and g(x)=x−2 Step 1 of 2: Find the formula for (f+g)(x) and simplify your answer. Then find the domain for (f+g)(x). Round your answer to two decimal places, if necessary.

Answer 1

(f+g)(x) = f(x) + g(x) = x^32 + x-2

domain is any real number

but "x32" is a strange way to write a term. probably you meant x^32, or possibly you meant 32x

if you meant 32x then (f+g)(x) = 32x +x -2 = 33x -2

but without more information, such as some restrictions on x, there is no way to "round the answer to two deimal places" or round it to any number

or maybe you meant x/32? if so then (f+g)(x) = x/32 +x -2 = (x+32x)/32 -2 = 33x/32 -2

in each case, the domain is any real number, without more information