Raymond B. answered 05/06/22
Math, microeconomics or criminal justice
A = LW = 126 = (4+2W)W = 4W + 2W^2
2W^2 + 4W -126 = 0
W^2 + 2W - 63 = 0
(W +9)(W -7) = 0
W = 7 wide
L = 2(7)+4 = 18 long
7x18 = 126
dimesnions are 7 by 18
Ayanna S.
asked 05/06/22The length of a rectangle is 4 units longer than twice its width. If the area is 126 square units, find the length and width.
Raymond B. answered 05/06/22
Math, microeconomics or criminal justice
A = LW = 126 = (4+2W)W = 4W + 2W^2
2W^2 + 4W -126 = 0
W^2 + 2W - 63 = 0
(W +9)(W -7) = 0
W = 7 wide
L = 2(7)+4 = 18 long
7x18 = 126
dimesnions are 7 by 18
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