-5y=-4x-45 perpendicular lime that goes through (16,-3)

Question

A line has this equation -5y=-4x-45

Write an equation for the perpendicular line that goes through (16,-3)

Answer 1

-5y = -4x -45

y =4x/5 + 9 has slope =4/5

a perpendicular line has slope -5/4, the negative inverse

y = -5x/4 + b

-3 =-5(16)/4 + b

-3 =-5(4) +b

-3 =-20 +b

b =-3+20

b=17= the y intercept of the perpendicular line

y = -5x/4 +17 is the perpendicular line through the given point (16,-3)