Alexis G.
asked 04/29/22Rate of Change for gas pressure
I've watched several videos and looked at similar problems and plugged in my numbers, but I still get the wrong answer. I'm not sure where I am going wrong.
The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV = nRT,
where n is the number of moles of the gas and R = 0.0821
is the gas constant. Suppose that, at a certain instant, P = 7.0 atm
and is increasing at a rate of 0.15 atm/min and V = 12 L
and is decreasing at a rate of 0.17 L/min. Find the rate of change of T with respect to time (in K/min) at that instant if n = 10 mol.
(Round your answer to four decimal places.)
1 Expert Answer
Eric C. answered 04/30/22
Engineer, Surfer Dude, Football Player, USC Alum, Math Aficionado
Hi Alexis,
Let's start by defining terms:
PV = nRT
P = Pressure (atm)
V = Volume (L)
n = Number of Moles (#)
R = Gas Constant (atm*L/(mol*K))
T = Temperature (K)
The problem gives several of these values:
P = 7
V = 12
n = 10
R = 0.0821
They don't give you T, but you can determine that from the other four values.
T = PV/nR
T = (7*12)/(10*0.0821)
T = 102.3143 K
We'll find out later we don't actually need it though.
They give you two other pieces of information:
"Pressure is increasing at a rate of 0.15 atm/min." This means dP/dt = 0.15
"Volume is decreasing at a rate of 0.17 L/min." This means dV/dt = -0.17.
It asks you to find "The rate of change of T with respect to time". So they're looking for dT/dt.
In order to generate these terms, we'll need to implicitly differentiate the ideal gas equation. We need to consider P, L, and T as variables. R and n can be considered constants.
PV = nRT
d/dt(PV = nRT)
We'll differentiate the sides one by one.
Since P and V are both variables, we need to apply the product rule to the left side.
d/dt(PV) = (1)*dP/dt*V + P*(1)*dV/dt
d/dt(PV) = V*dP/dt + P*dV/dt
On the right side of the equation, T is the only variable. You can consider "nR" as a single constant who's just along for the ride.
d/dt(nRT) = nr*dT/dt
So:
V*dP/dt + P*dV/dt = nr*dT/dt
Plug in all your known values.
P = 7
V = 12
n = 10
R = 0.0821
dP/dt = 0.15
dV/dt = -0.17
(12)*(0.15) + (7)*(-0.17) = (10)*(0.0821)*dT/dt
1.8 - 1.19 = 0.821*dT/dt
0.61 = 0.821*dT/dt
dT/dt = 0.7430 K/min
Is this the answer you got?
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Doug C.
Can you give an idea of what you have tried? Did you use product rule on left hand side? Did you find the derivative with respect to time on the right hand side as nR dT/dt?04/29/22