Raymond B. answered 04/16/22
Math, microeconomics or criminal justice
175(.05) + .6x = (175+x).25
.6x -.25x = (175)(.25-.05)
.35x = 175(.2) = 35
x = 35/.35 = 100 mL of 60% needed to obtain a 25% mixture
Diana D.
asked 04/15/22You need a 25% alcohol solution. On hand, you have a 175 mL of a 5% alcohol mixture. You also have 60% alcohol mixture. How much of the 60% mixture will you need to add to obtain the desired solution?
Raymond B. answered 04/16/22
Math, microeconomics or criminal justice
175(.05) + .6x = (175+x).25
.6x -.25x = (175)(.25-.05)
.35x = 175(.2) = 35
x = 35/.35 = 100 mL of 60% needed to obtain a 25% mixture
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