PLEASE HELP!!!!!!!!

Question

Biologists stocked a lake with  fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be . The number of fish grew to 980 in the first year.

a)Find an equation for the number of fish  after  years    

.b) How long will it take for the population to increase to  (half of the carrying capacity)?It will take__________  years.

You may enter the exact value or round to 2 decimal places

Answer 1

980=800e^r

98= 80e^r

49 =40e^r

e^r = 49/40

r = ln(49/40)

r = about .20294

r=20.29% growth rate

P(t) = 800e^0.20294t

5000 = 800e^.20294t

25/4 = e^.20294t

.20294t = ln(25/4) = 1.83258

t = 9.03 years to reach 5,000