
Nataliya D. answered 03/24/13
Patient and effective tutor for your most difficult subject.
(b) A = - (9/96)t + 10 or A = - 0.094 · t + 10
↓
the initial acreage
Jamal M.
asked 03/24/13In 1904, the glacier on this peak covered 10 acres. By 2000 this glacier had melted to only 1 acre.
(a) Assume that this glacier melted at a constant rate each year find this yearly/acres rate? (Type a integer or a decimal and round to the nearest thousandth
(b) Use the answer to part (a) to write a linear equation that gives the acreage A of this glacier t years past
Nataliya D. answered 03/24/13
Patient and effective tutor for your most difficult subject.
(b) A = - (9/96)t + 10 or A = - 0.094 · t + 10
↓
the initial acreage
Asok B. answered 03/24/13
Ph. D in Biochemistry, willing to teach Chemistry, Biochemistry, Math
In 96 years total loss is 9 acres. Therefore yearly loss= 9/96 Acres/year = 0.09375 acres/year
If Loss of acreage is L in time "t" years, then L= 0.09375t.
So the Equation is A= A0 - 0.09375t where A0 is the initial acreage and A is the acreage after "t" years.
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