Find the absolute maximum value and the absolute minimum value, if any, of the function.

Question

g(x)= x√(25-x²) on [0,5]

maximum=

minimum=

Answer 1

find f(0)=0 and f(5)=0 ... f'(5/√2)= 25/2 ... (x=5/√2 is crititcal point in the range specified). Thus abs max=25/2 and abs min =0