Raymond B. answered 03/27/22
Math, microeconomics or criminal justice
35F + 40S = 2600
F +S = 70
35F +35S = 35(70) = 2450
subtract last equation from 1st to eliminate one variable
40S -35S = 2600 -2450
5S = 150
S= 150/5 = 30 mpg for the 2nd car
F =70-30 = 40 mpg for the 1st car
35(40) + 40(30 = 1400 + 1200 = 2600