Jordyn B.

asked • 03/24/22

A jar contains 6 pennies, 14 nickels, 16 dimes, and 4 quarters. If one coin is chosen at random, find the probability as a percent. P(worth at least 5 cents) =

Kyle K.

The answer would be 7.2 1/3 because if you look at the question algebraically you’ll notice that the perimeter of the jar is 5.3 and if you were to divide the jars perimeter by the number of coins in total you would come upon the realization of the true answer which is 7.2 1/3
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03/24/22

Danny H.

tutor
P(worth at least 5 cents) = 1 - P(worth less than 5 cents) = 1 - P(penny) This can be rewritten as 1 - (# of pennies / total number of coins in the jar) The # of pennies is 6. The total # of coin in the jar is 6+14+16+4 = 40 Therefore, our final expression is 1 - (6/40) = 0.85 0.85 expressed as a percentage is 85%. I'm not sure if Kyle K. was answering a different question, but you should ignore his answer.
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03/24/22

2 Answers By Expert Tutors

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James W. answered • 03/24/22

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Let's look at the coins by sections


  1. 6 pennies: 1 cent each
  2. 14 nickels: 5 cent each
  3. 16 dimes: 10 cent each
  4. 4 quarters: 25 cent each
  5. total coins: 40

Which coins are worth at least 5 cent?


The nickels, dimes and quarters,


14 nickels + 16 dimes + 4 quarters = 34 coins are worth at least 5 cent


Therefore, P(coins are worth at least 5 cent) = # of coins worth at least 5 cent / total coins

P(coins are worth at least 5 cent) = 34 / 40 = 0.85 or 85%


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