Find the slope-intercept form for the line satisfying the the following conditions.

Question

x-intercept 2, y-intercept 3/5

Answer 1

 

The slope intercept form of a linear equation is

y=mx+b

y is the y coordinate of a point on the line  (X,Y)  

m is the slope

x is the x coordinate of a point on the line (x,)

b is the y-intercept--the point on the y-axis where this line crosses.

 

if y=mx+b

then with your data  there is a point where the line crosses at 2 on the x-axis  (2,0)

so you can write y=mx+b as 0=m(2)+3/4

0=m(2)+3/4

-3/4=m(2)

-3/4 is divided by 2

-.375=m

the equation becomes y=-.375x+.6

 

Answer 2

Using the slope form to find the slope of both intercepts:

 m=slope

m=(Y2-Y1)/(X2-X1)  Slope form

Let

(X1, Y1) = (2,0)           X intercept

(X2, Y2) = (0,3/5)       Y intercept

So that

             m=(3/5 - 0) / (0 -2)

                =(3/5) / (-2)

                = 3/5 * (-1/2)

              m= -3/10

Finally By slope intercept form

                y=mx + b

                m=-3/10

                b= y intercept=3/5

The solution is: y = -3/10X + 3/5