A volleyball is thrown into the air. The function h=-16t^2+48x+3 represents the height (h) of the volleyball after t seconds. After how many seconds will it hit the ground?

Answer 1

-16t^2 +48t +3 = 0

use the quadratic formula

t = -48/-32 + (1/32)sqr(48^2 +4(16(3) = 3.06 seconds to hit the ground

h' =-32t + 48 =0

t =1.5 seconds to reach max height of -16(1.5)^2+48(1.5)+3 =39 feet

it takes 3 seconds to go up and come down to the original height of 3 feet, then about 0.06 second more to reach the ground