The sum of two numbers is 6 . three times the larger number plus three times the smaller number is 36. Find the numbers.

Answer 1

x+y = 6

multiply by 3

3x +3y = 18

that contradicts "3 times the larger" + "3 times the smaller 36

3x+3y = 36

graph them, they're parallel lines with no intersection. The equations have no solution

or maybe "3 times (the larger plus 3 times the smaller) = 36 means

3(x+3y) = 36

3x + 9y = 36 subtract

3x + 3y = 18

6y = 18

y = 18/6 = 3

x= 6-3 = 3

but the problem refers to a "larger" and "smaller" number

3 is not larger or smaller than 3

there is no solution