The sum of two numbers is 6 . three times the larger number plus three times the smaller number is 36. Find the numbers.

Answer 1

x+y = 6

y = 6-x

3x +3y = 36

3x +3(6-x) = 36

3x +18-3x = 36

3x -3x = 36-18

0 = 18 is a contradiction.

there is no solution

but maybe the problem was really

3(x+3y) =36

3x +9y = 36, subtract 3 times x + y = 6

3x +3y =6(3)

6y = 18

y=18/6=3

x =6-3 =3

but 3 is not greater than 3. there is "larger" and "smaller" number

if x>y or y>x, then there is no solution