If you factor the numerator you find out there is a "3 - x" factor in it that cancels with the "3 - x" in the denominator:
This manifests itself as a hole in the graph at x = 3 (so (3, 2)) and not a vertical asymptote. So answer (e) is correct.
Sarah C.
asked 03/11/22Explain why there is no vertical asymptote when a superficial examination of the function may indicate that there should be one.
(a) The graph is a vertical line
(b) The function does not have a discontinuity.
(c) There is a jump discontinuity at (3, 2).
(d) The denominator is never equal to zero.
(e) There is a hole at (3, 2).
If you factor the numerator you find out there is a "3 - x" factor in it that cancels with the "3 - x" in the denominator:
This manifests itself as a hole in the graph at x = 3 (so (3, 2)) and not a vertical asymptote. So answer (e) is correct.
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